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[DhtmlXQ_adddate]2020-10-07 04:52:39[/DhtmlXQ_adddate]
[DhtmlXQ_editdate]2020-10-07 04:52:39[/DhtmlXQ_editdate]
[DhtmlXQ_title]第117局 炮高兵士相胜单炮象[/DhtmlXQ_title]
[DhtmlXQ_binit]9999999958484799999929999999995399994299319999999930999999999999[/DhtmlXQ_binit]
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[DhtmlXQ_comment0]本局红方要炮相联合禁黑单象于’边隅，再兵帅控制中路。然后运用弃士手段破坏黑方“将前炮后”的防守形式而胜[/DhtmlXQ_comment0]
[DhtmlXQ_comment8]黑如炮5进8，则炮三进五(切忌炮三平五，因黑炮5平2，兵六进一炮2退6,相三退五象7退5,兵六平五将5平4，红方||无法取胜)，以下成“炮高兵单相必胜单炮”的残局。详见第92局。[/DhtmlXQ_comment8]
[DhtmlXQ_comment17]红胜。[/DhtmlXQ_comment17]
[DhtmlXQ_comment2_17]红胜。[/DhtmlXQ_comment2_17]
[DhtmlXQ_comment3_7](弃士，这是破坏黑方最佳防守形式的巧妙着法)[/DhtmlXQ_comment3_7]
[DhtmlXQ_comment3_17]绝杀;[/DhtmlXQ_comment3_17]
[DhtmlXQ_comment4_6](如炮4平5，胜法同主变)[/DhtmlXQ_comment4_6]
[DhtmlXQ_comment4_19]得象胜。[/DhtmlXQ_comment4_19]
[DhtmlXQ_comment5_13]红胜。[/DhtmlXQ_comment5_13]
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